resource upgrade potential, page-2

thegun,
I need to make some assumptions. These are
a) width of strike is 100m
b) depth of strike is 100m
c) Fe content is 62%

So volume = 20000*100*100 sqm
= 200,000,000 sqm

Density of iron = 7.85

Tonnes of iron ore at 100% fe = 200,000,000 *7.85
= 1.57 Billion tonnes

At a 62% iron content = 1.57 B * .62
= 973,400,000 tonnes

I am not a geologist or a mining engineer, so I am happy to be corrected on my calculations