what's it going to take to raise sp??, page-15

Hi all, Having a busy few days and not much time to write HC posts I'm sorry to say. A few quick answers to some of your questions plus a couple of other points.
Firstly grar and the fertiliser: its frustrating not knowing how many tonnes of resource are associated with this latest 110m of high grade mineralisation, but to do a JORC resource, the company needs to define the geometry of this part of the M1 orebody. It's a specific rather then a general location so waffling on about a "conceptual" target is inappropriate. After all this is one target the company has hit already so its well past the "conceptual stage"

Secondly a point of my own. I can make forward looking statements and not be constrained by JORC so I'm going to make one of these statements right now. Understand this is conjecture on my part but it is based on the structure of other ore veins in the Hawkins Hill/Reward mine. Other veins have a vertical extent of well over 100m. High grades shoots can be 50 or more metres "up dip". (Up dip is a measure upwards along a structure rather than vertical. The ore veins dip at angles of around 60 to 80 degrees.) I'm going to guess that the high grade portion M1 is 40m up dip. I hope I'm wrong and it is 200m up dip but 20m is possible too. The only way the company is going to actually measure this aspect of the M1 geometry is by putting in about 30 diamond drill holes. Right now there are many more cost effective places to drill.

Back to my 40m. With this number I've just "made up", no let me call it an educated guess, I'm going to calculate an answer to plough's question. The company tells us the high grade M1 mineralisation is 110m long, 1.1m wide and grades at an average of 35.4g/t. I need to recalculate the width at right angles to the dip. 1.1m X cos 30= 0.95m.

Volume of mineralised vein = 110mX40mX0.95m=4180 cubic metres.

Mass of mineralisation = volume X density = 4180 X 2.6 = 10868 tonnes.

Gold content = 10868 X 35.4 = mass X grade = 384727g

Gold recovery = gold content X mined proportion X plant efficiency

= 384727 X 80% X95% = 292393g (9400 oz) assuming 20% is left unmined.

The company will be able to mine more than 80% of this vein if they can switch switch from open stoping operations to cut and fill. In addition the M2 vein is very close by and both veins may be extracted together.