Well, I reckon your shaded section is about 6k long x 2.5 k wide = 15 km2, divided by 2 as its triangular so 7.5 km2
6000 X 2500 X 150 /2 = 1,125,000,000 m3.
Someone else can work out the rest
Ann: Highly Conductive Brines Discovered in Fifth Drillhole, page-49
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