environment court decision, page-14

Thanks Cdchi1

I have Year 1 as 270,000 tpa @ 5.1 g/t Avg / 31.1034768 (troy ounce) = 44,271 oz x recovery rate of 95.7% = 42,367oz

Years 2,3,4,5,6 = 333,000 tpa @ 5.1 g/t Avg / 31.1034768 (troy ounce) = 54,109 oz x recovery rate of 95.7% = 51,782

Total Year 1 = 42,367
Total (Yr 2-6) = 258,910
TOTAL = 301,277

So there is obviously further dilution at some point in the production process. Is this occuring at the mine site or when we truck the stuff to Parkes?

Any further insight would be much appreciated