Ann: Anson Confirms Supersaturated Brines in Gold Bar Sampling, page-37

1 Litre is 0.001 m^3

Assuming a well radius of 60mm ( Minimum 120mm dia, not really sure what the size is but that seems to be as small as oil well come)

Volume = pi*r^2 * h
0.001 = pi* 0.06^2 * h

Solving for height, there is a litre every 'h' i.e. 0.0884 m

Zone 29: 7020 foot deep = 2139 m

Therefore the hole contains 24196 Litres @ 1.24 Kg/L ( 10.35 lb/Gal)

Thats 30 003 Kg = 294 029 Newtons

At the bottom of the well area in mm is pi*r^2 = 11309.4 mm^2

therefore pressure is 26 Mpa

= 3770 Psi for a well that is constantly 120mm wide....