Honestly went really simple, I haven’t got the Ann’s in front of me so I’m just going to keep it basic.
from the graphs of the good set of results: I took the estimated width and length of the anomaly, and from another graph the average depth to determine the tonnage in that area, it was something along the line of 500m x 200m x 100average depth. Totalled something like 50mil metre cube of ground. Which is about 75mil tonne of ground (1.5ish tonne to metre cube) @average 1g/tonne converted to ounces.
really rough numbers until I can find decent software that will let me calculate the full cubic metres of area. And then I might be able to define sections with the results of the Ann’s but I don’t have time or the software to do it.
anyway I got my results from around 75mil tonne of dirt at 1g per tonne average. divide by 28 to get to ounces so 2.6million
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