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Some back of the envelope calcs for capex of a fermentation...

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    Some back of the envelope calcs for capex of a fermentation plant:

    https://youtu.be/P3bXclXWOTw?t=71
    This video implies a yield of 1 ton of MC per 60,870 litres (100m * 700m * 1,000l = 7,000,000l / 115).

    Lets round down to 50,000 litres to be safe.

    https://www.alibaba.com/product-detail/High-Quality-Large-Capacity-Brewing-System_1600224613099.html?spm=a2700.galleryofferlist.normal_offer.d_image.71134ffd85RpGR
    Picked the one with the roundest number for simplicities sake.

    10 tons of MC would require 500,000l of fermentation capacity or US $100,000 (10 * 10,000l fermentation tank).

    No idea what infrastructure costs would be, but perhaps double it. So hazarding a guess at US $200,000 for 10 tonnes of MC production every 15 days, not bad...

    Another complete guess but an 80% yield to fibre would mean approximately 40 tonnes of Nullarbor-20 (10 * 0.8 * 5).


 
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