flurnt, I am trying to follow your logic in respect to 4% Chalcopyrite i.e.
Iron 30.43 % Fe
Copper 34.63 % Cu
Sulfur 34.94 % S
______
100.00 %
Can you for all of us please explain? Are you suggesting that Cu at 1.28% is 'different' to 4% @ 34.63%? Just trying to develop a better understanding in respect to potential costs associated.
Thanks in advance, NL