darts anyone, page-3

  1. 1,182 Posts.
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    The probability of it NOT happening goes like this...

    Area of a sphere: A = 4 * pi * R^2

    Area of a cap: a = 2 * pi * R * h {where h is the height of the cap}

    Let's use a unit sphere: R = 1

    So:
    A = 4 * pi
    a = 2 * pi * h

    So probability for each cap is:
    p = h / 2

    Observe that the area is linear in "h", and that the probability is linear in "h".

    So the overall probability is:
    P = (p[h = 0] + p[h = 1]) / 2
    P = ((0 / 2) + (1 / 2)) / 2
    P = 1 / 4

    The math there is kind of tough sledding, and one of my principles is that one doesn't understand anyting unless one can explain it to an eight year old so:

    Their proof goes like this...

    Let's call the points A, B, C, and D.

    Any two points define a great circle.

    Take the circle defined by A + B, pick the hemisphere C is in, then it's 50% that D is also in it.

    Take the circle defined by A + C, pick the hemisphere B is in, then it's 50% that D is also in it.

    Take the circle defined by B + C, pick the hemisphere A is in, then it's 50% that D is also in it.

    Probability that D was in none of them = (1 / 2)^3 = 1 / 8

    Makes the answer 87.5%

    I have no friggin idea so I googled it. I hope you math guru's appreciated my cut and paste because I still have no friggin idea.
 
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