''On average, the waste from a reactor supplying a person’s...

''On average, the waste from a reactor supplying a person’s electricity needs for a year would be about the size of a brick.''

really?

Therefore, the volume of 25 million standard bricks would be approximately 33,202 cubic meters. ---------- per year

''To calculate the volume of 25 million bricks, we need to know the dimensions of a standard brick. While brick sizes can vary, let's use the dimensions of a common standard brick for this calculation.
A standard brick typically measures:
- Length: 230 mm
- Width: 76 mm
- Height: 76 mm
The volume of a single brick would be:
230 mm x 76 mm x 76 mm = 1,328,080 cubic millimeters (mm³
To convert this to cubic meters (m³, we divide by 1,000,000,000 (as there are 1 billion mm³ in 1 m³:
1,328,080 mm³ ÷ 1,000,000,000 = 0.00132808 m³ per brick
Now, to calculate the volume of 25 million bricks:
0.00132808 m³ x 25,000,000 = 33,202 m³
Therefore, the volume of 25 million standard bricks would be approximately 33,202 cubic meters.
To put this into perspective:
1. This volume would be equivalent to about 13 Olympic-sized swimming pools.
2. If stacked in a single column, these bricks would reach a height of about 1,900 kilometers, which is roughly 237 times the height of Mount Everest.
It's important to note that this calculation doesn't account for any mortar or gaps between bricks in actual construction, which would increase the total volume in a real-world scenario.

[1] https://www.pghbricks.com.au/product-info/brick-calculator
[2] http://www.brickbat.co.uk/brickproduction.htm
[3] https://www.bartneck.de/2019/04/21/lego-brick-dimensions-and-measurements/
[4] https://phys.libretexts.org/Bookshe...e_(OpenStax)/11:_Fluid_Statics/11.02:_Density
[5] https://community.databricks.com/t5/data-engineering/volume-limitations/td-p/63935