While I was shooting some hoops, a question came to me; a...

While I was shooting some hoops, a question came to me; a question that blew my mind.

I asked myself "what would be the chances that bisantrene would be more significant than the next most potent FTO inhibitor"

We are going to assume that my preivous commentary stands true and for this case I will use p = 0.01. I have done this because the light blue box almost fits into the gap between bisantrenes top and brequinars top.

What a p value of 0.01 means is that it is 99% likely that bisantrene is significantly different to brequinar.

Right. So now we understand that, we need to ask ourselves the question;

What are the chances that bisantrene would be 99% more significant than the next most potent FTO inhibitor?

My answer to that is that it would be 1% of 260,000.

Therefore, the chance of being 99% significantly different than the next most potent inhibitor of FTO is 1 in 26,000,000.

To put this into context:

Chance of winning division one lotto in Australia: 1 in 8,145,060

That means that you have 3 times better chances of winning division one lotto in Australia than bisantrene being more significant than the next most potent FTO inhibitor.

From what I can see, it looks like bisatrene most certainly might be.

All IMO.

P.S. At a significance level of p = 0.001 (which may well be the case), the chances are 1 in 260,000,000, which is awfully close to the chance of winning the powerball jackpot (1 in 292,201,338).