SEEMS TIME TO GIVE UP, page-372

Here is the formula that I used:

=(G25+G26+G27+G28+G31)*K26/G3+(G24+G25+G26+G27+G28+G29+G30+G31)*(750000-K26)/G3

K26=445,055 (tons of stockpile ore of 0.6g/t grade i.e. over 54days)
750,000 is the qtrly tonnage processed.

Also to arrive at the 27,120oz of gold, the grade of the processed ore will have to be 2.1g/t and there has to be (750000-445055) tons of them to be processed over the 37days. Is there going to be enough tonnage? I don't know but this is just on the assumption that DCN has enough ores of this quality. Now according to JC, the grade from Mt Malvern was around the 2g/t range and the key issue is if there is enough of them.

The rest, if you are smart enough, you can figure that out from the cells below.

If there is any error in my formula or assumptions, please by all mean correct me and you will very much appreciated.

Hope to hear from you soon.

Cheers.