BTE3 is to test the boundary, so could be 12km from BTE2. Found nothing with BTE3 and decided to halve the distance - "binary search technique". Therefore, BTE5 is half way between BTE2 and BTE3.
Could be:
BTE2 to BTE3 = 12km
BTE2 to BTE5 = 6km
BTE3 to BTE5 = 6km.
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BTE3 is to test the boundary, so could be 12km from BTE2. Found...
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