the size of the resource

This us a link to the Federal Bureau of Land Management's decision, with a comprehensive outline of the Mining Plan of Operations (MOP) and comments on all aspects of the mine and appoval process:


http://www.blm.gov/pgdata/etc/medialib/blm/ut/monticello_fo/Minerals/daneros_mine_project.Par.20380.File.dat/Final%20Environmental%20Assessment%20and%20Decision%20Record.pdf



An extraxt from p 25 of the pdf:

'Ore Stockpiles
The ore stockpile pad would be located on a 17-foot-thick historical waste dump from the nearby
McCarty–Coleman Decline. Approximately 100,000 tons of ore would be mined over seven years. The
maximum production of ore over a two-week period would be 4,000 tons. The ore stockpile would cover
approximately 0.26 acre of the old waste rock dump. No processing of ore would occur at the site. Ore
would have an average grade of 0.3 percent U308, sulfur levels would average 2.6 percent in shipping
ore, and average copper grade would average 1.0 percent. Levels of other metals such as lead, zinc,
nickel, mercury, and arsenic are low. The ore is carbonate rich, in the form of dolomite and calcite. Ore
would not be stored on site for long periods but would be transported to the White Mesa Mill near
Blanding on a daily or near-daily basis. Ore would be transported via County Road D0029 to County
Road B258 and then to State Highway 95.'


How much Uranium is this?

Any experts out there who can quantify this??

100,000 t = 1,000,000,000 kg

1 kilogram = 2.20462262 pounds

1,000,000,000 * 2.20462262 = 220462262 pounds


220462262 pounds of ore @ 0.3% U308


220462262 * 0.003 = 661386.786 pounds of uranium



Any thoughts people?


Cheers