"1 U.S. gallon (0.83 imperial gallons; 3.8 liters) of fuel is equivalent to 33.7 kWh, according to the US Department of Energy
[a certain] electric truck uses 2 kilowatt-hours per mile which is the equivalent of using only 10 kWh per every 5 miles (8 km). The diesel truck that it replaces uses the equivalent of 33.7 kWh per 5 miles (8 km). Thus, the diesel truck is using 3.37 times the amount of energy that the electric truck is using.
Therefore, the only variables that are stopping commercial use of electric trucks are original vehicle cost and driving range, owing to the high battery pack cost and low specific energy."
so, where can the [technical] solution be found?
"With a higher specific energy fewer cells are needed to build a battery pack. This results in a lower cost.
Inactive cell materials such as tabs and containers account for roughly 36% of the total cell materials cost. These other cell materials do not add energy content to the battery. Therefore, reducing inactive materials reduces the weight and size of battery cells without reducing energy content. This drives interest in improving cell design with innovations."
