Hole CDP_021: 17.6mts @ 1,292 g/t Ag & 11m @ 0.25% Cu, 16.41m from 101m Any one ? Why is the depth important especially ATM ?
Yes that's 17.5 mt intersection at 1,292 g p/t Silver-Equivalent at current silver to gold ratio of 85-01 eg 85 OZ of Silver buy's one Oz gold . Is equivalent of 15.2 g p/t Gold p.s.- little to none in the way of dilution issues with 17.5 mt intersections. salt
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